ImageVerifierCode 换一换
格式:PDF , 页数:18 ,大小:536.42KB ,
资源ID:422129      下载积分:5000 积分
快捷下载
登录下载
邮箱/手机:
温馨提示:
如需开发票,请勿充值!快捷下载时,用户名和密码都是您填写的邮箱或者手机号,方便查询和重复下载(系统自动生成)。
如填写123,账号就是123,密码也是123。
特别说明:
请自助下载,系统不会自动发送文件的哦; 如果您已付费,想二次下载,请登录后访问:我的下载记录
支付方式: 支付宝扫码支付 微信扫码支付   
注意:如需开发票,请勿充值!
验证码:   换一换

加入VIP,免费下载
 

温馨提示:由于个人手机设置不同,如果发现不能下载,请复制以下地址【http://www.mydoc123.com/d-422129.html】到电脑端继续下载(重复下载不扣费)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: 微信登录  

下载须知

1: 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。
2: 试题试卷类文档,如果标题没有明确说明有答案则都视为没有答案,请知晓。
3: 文件的所有权益归上传用户所有。
4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
5. 本站仅提供交流平台,并不能对任何下载内容负责。
6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

版权提示 | 免责声明

本文(AGMA 11FTM11-2011 Marine Reversing Main Gear Rating Factor Versus Number of Loading Reversals and Shrink Fit Stress.pdf)为本站会员(feelhesitate105)主动上传,麦多课文库仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知麦多课文库(发送邮件至master@mydoc123.com或直接QQ联系客服),我们立即给予删除!

AGMA 11FTM11-2011 Marine Reversing Main Gear Rating Factor Versus Number of Loading Reversals and Shrink Fit Stress.pdf

1、11FTM11AGMA Technical PaperMarine Reversing MainGear Rating FactorVersus Number ofLoading Reversals andShrink Fit StressBy E.W. Jones, S. Ismonov andS.R. Daniewicz, Mississippi StateUniversityMarine Reversing Main Gear Rating Factor Versus Number ofLoading Reversals and Shrink Fit StressE. William J

2、ones, Shakhrukh Ismonov and Steven R. Daniewicz, Mississippi StateUniversityThe statements and opinions contained herein are those of the author and should not be construed as anofficial action or opinion of the American Gear Manufacturers Association.AbstractThe marine vessel reversing main gear to

3、oth is subjected to three different loading cycles:- Ahead travel with load pulsing from zero to 100% of full power;- Astern travel with load pulsing from zero to about minus 66% of full power;- Reversal of direction with load changing from 100% of full power to about minus 66% of full power.Thenumb

4、erofrepetitionsofthesethreedifferentloadingcyclesvarieswiththevesseldutycycleandlife. Thepublishedvaluesofallowabledesignstressforteetharebasedonpulsingloads,whichmustbe modifiedforthisthirdloadingcycle. Thetoothmayalsobesubjectedtomeanstressduetoshrinkfittingofthegearontoahub.This paper evaluates t

5、he derating factor for marine reversing main gear tooth allowable bending stressusing the Goodman fatigue line and Miners equation as a function of the average number of changes invessel direction per hour, shrink fitting stress values, and different materials based on the AGMA valuesfor allowable s

6、tress and life factor.Copyright 2011American Gear Manufacturers Association1001 N. Fairfax Street, 5thFloorAlexandria, Virginia 22314October 2011ISBN: 978-1-61481-010-03 11FTM11Marine Reversing Main Gear Rating FactorVersus Number of Loading Reversals and Shrink Fit StressE. William Jones, Shakhrukh

7、 Ismonov and Steven R. Daniewicz,Mississippi State UniversityIntroductionTheobjectiveofthiswork,whichwasinitiatedbytheAmericanGearManufacturersAssociationMarineUnitsCommittee, is to adjust the allowable tooth stress derating factor for the marine vessels reversing main geartomatchthevesselsdutycycle

8、andshrinkfittingstresses. Thetoothflankofamarinevesselsreversingmaingear experiences three different types of load cycles as illustrated in Figure 1 and described below.- Pulsing, tensile bending stress cycles occur during ahead travel, which vary from zero to smax.- Pulsing, compressive bending str

9、ess cycles occur during astern travel, which vary from zero top smax. The value of p is the ratio: astern torque divided by ahead torque.- Onehalfofareversingbendingfatiguecycleoccurseachtimethedirectionofthevesselisreversed. Thestress varies between smaxand p smax.Thefatiguelifeofthereversingmainge

10、artoothisafunctionofthenumberofrepetitionsofthesethreeloadingcycles, which vary with the vessels duty cycle, and the design life. The fatigue life may also be affected bystresses induced into the tooth flank by shrink fitting the gear to the shaft.Current design practice is similar to treatment of a

11、n idler gear tooth, which has the allowable bending stressnumber reduced by a derating factor to compensate for the reduction in fatigue strength when the stress ischanged from uni-directional pulsing to fully reversing bending stress. For an idler gear tooth, a deratingfactor of 0.7 is given by the

12、 American Bureau of Shipping Rules 1, MAAG Gear Book 6 and ANSI/AGMA2001-D04 2. A derating factor for the reversing main gear tooth allowable bending stress number of 0.9 isspecifiedbytheAmericanBureauofShippingRulesandInternationalAssociationofClassificationSocieties,LTD12toaccountfortheinfluenceof

13、thereversingtoothstressandthestressatthetoothduetoshrinkfittingof the gear onto the shaft.Figure 1. Tooth bending stress during ahead travel, reversal of direction, astern travel, andreversal back to ahead travel4 11FTM11This study estimates the deratingfactor forthe allowablebending stressnumber as

14、a functionof theaveragenumberofvesselreversalsperhourofoperation,thenumberofstresscyclesduringaheadtravel,thenumberofstresscyclesduringasterntravel,andtheshrinkfitstressinducedatthetoothflank. Thisanalysisisbasedon the Goodman fatigue line, Miners Rule, allowable stresses per AGMA, and Life Factors

15、for bending perAGMA.Material strengthValuesoftheallowablebendingstressnumber,sat,fordifferentgearsteelsunderpulsingloads arepublishedin ANSI/AGMA 2001-D04 based on 99% reliability for 10,000,000 cycles. A lifefactor, YN,adjusts theseval-ues for different numbers of load cycles. Gear fatigue strength

16、 is determined experimentally under pulsing,i.e. onedirectionalloadingofa“non-running”geartooth10. Thestressconcentrationfactorisincorporatedas a stress increasing term via the geometry J-factor. The materials fatigue ratio, M, is the ratio of fullyreversing load fatigue strength, Sf, to ultimate te

17、nsile strength, Su. Values of Mvary between 0.35 and 0.6 forSuvalues less than 200,000 psi and tend to be constant for larger values of Su9.(1)M =SfSuwhereM material fatigue ratio;Sfis fatigue strength;Suis ultimate strength, psi.Goodman fatigue lineThe Goodman fatigue line defines the relationship

18、between alternating stress, sa, mean stress, sm, fatiguestrength,Sf,andultimatestrength,Su. TheGoodmanfatiguelinerepresentsthefatiguefailureofhighstrengthsteelsquitewell,butductilematerialsfollowtheGerberlinemoreclosely.3 Basedonthefactthatcompress-ive mean stresses at long lives are beneficial, the

19、 modified Goodman equation canbe convenientlyextrapol-ated to the compressive mean stress region as shown in Figure 2. 9 Theequation forthe Goodmanfatigueline, which lies between the yield lines, is shown in Figure 2.(2)saSf+smSu= 1The load ratio is defined as:R =sminsmaxThe alternating and mean str

20、esses are:(3)sa=smax smin2(4)sm=smax+ smin2wheresais alternating stress, psi;smis mean stress;R is ratio of minimum to maximum stress values;sminis minimum stress, psi;smaxis maximum stress, psi.Combining the above equations gives the Goodman equation as follows:(5)smax(1 R)2 Sf + smax(1 + R)2 Su =

21、15 11FTM11Figure 2. Fatigue and yielding criteria for constant life as a function of alternating and meanstresses, modified Goodman diagram.Idler gear tooth derating factorThe idler gear teeth are subjected to fully reversing bending stresses. The published allowable gear toothbending stresses, whic

22、h are based pulsing loads, are derated by a factor to produce equivalent fatiguestrength for a fully reversing bending cycle. The following example showing how this derating factor may beobtained for the idler will indicate part of the theory used for the development of the derating factor for there

23、versing main gear tooth. The bending stress in the idler tooth varies from Ki satto Ki sat.Thederating factor, Ki, must be multiplied times the AGMA published allowable stress number, sat, to obtain theallowable stress number for an idler tooth. Therefore, the maximum and minimum stresses in the idl

24、er toothare:(6)smax= Kisat(7)smin= KisatwhereKiderating factor for satif all tooth load cycles are fully reversing;satis published allowable stress number.For fully reversing loading of the idler teeth, the endurance strength is Sfand R is minus one. Substitution ofEquations 6 and 7 into Equation 5,

25、 Goodmans equation, gives:(8)KisatSf+0Su= 1So, the “allowable bending stress number” as published by AGMA is equal to the endurance strength underfully reversing bending load, Sf, divided by a derating factor, Ki.(9)sat=SfKiWritetheGoodmanequation relatingthe pulsingstresses ofthe geartooth fatiguet

26、est tothe fatiguestrengthof the material, Sf:(10)sa=smax2=sat26 11FTM11(11)sm=smax2=sat2(12)sat2 Sf+sat2 Su= 1(13)sat=112 Sf+12 SuEquate equations for satabove to obtain:(14)SfKi=112 Sf+12 SuTherefore, the value of Kiis:(15)Ki=12+Sf2 SuSubstitute the fatigue ratio, per equation 1:(16)Ki=1 + M2The ab

27、ove equation is the same as given by Det Norske Veritas 10 for idlers, which have R equal to minusone. Values of the idler gear tooth derating factor, Ki, for different values of fatigue ratio, M, are given inTable 1. Note that when M equals 0.40, the value of Kiis 0.70 as specified in the literatur

28、e.Fatigue strength for fully reversing load on toothThe fatigue strength for a fully reversing load on a gear tooth as a function of number of fatigue cycles, N,isSf(N). Sf(N) varies along the Goodman fatigueline asa functionof thenumber ofcycles applied,N,whichisrepresented by the AGMA stress cycle

29、 factor, YN.2(17)Sf(N) = KiYNsatwhereYNstress cycle factor for bending strength.Forafatigueratio,M,of0.4,casecarburizedsteel,andsatof65,000psithevaluesofSf(N)aregiveninTable 2for 1,000, 3,000,000 and 1010cycles. These numbers of cycles are located at the ends of two straight lineportions on the log-

30、log plot of the YNversus cycles plot in ANSI/AGMA 2001-D04. 2Table 1. Idler gear tooth derating factor, Ki, for different values of material fatigue ratio, MFatigue ratio, M Idler tooth derating factor, Ki0.30 0.650.40 0.700.50 0.75Table 2. Fully reversing, bending tooth strength for case carburized

31、 AGMA Grade II steel fordifferent numbers of fatigue cycles.Number of cycles, N YNFatigue strength, Sf(N),for Ki= 0.70, psi1,000 2.70 Sf(103) = 123,0003,000,000 1.04 Sf(3 106) = 47,30010,000,000,000 0.90 Sf(1010) = 40,9507 11FTM11The fatigue strength, Sfa,when the number of cycles, N, is between 1,0

32、00 and 3,000,000 cycles may beobtained from the equation of a line:(18)logSfa= logSf103+log Sf3106Sf103log3106103log (N) log103The fatigue strength, Sfb, when the number of cycles, N, is between 3,000,000 and 10,000,000,000 cyclesmay be obtained from the equation of a line:(19)logSfb= logSf3 106+log

33、Sf1010Sf3106log10103106logN3 106whereSfaequivalent stress when 1,000 Na 3,000,000 cycles;Sfbequivalent stress when 3,000,000 Nb 10,000,000,000 cycles;Na number of life cycles at equivalent stress Sfa,if1,000 Na 3,000,000 cyclesNb number of life cycles at equivalent stress Sfb, if 3,000,000 Nb 10,000

34、,000,000 cyclesShrink fitting induced stresses at toothStresses over a section of a gear due to shrink fitting of the gear onto a shaft are developed for two differentgear designs, a solid gear and a fabricated gear. The specifications for the two gears are given in Table 3.Figure 3 shows the two ge

35、ars, Figure 4 and Figure 5 shows sections cut from half of each gear.Figure 3. Fabricated gear and solid gear8 11FTM11Table 3. Data for two gears analyzed in this study for shrink fitting induced stresses in tooth areaSolid gear Double helicalfabricated gearNormal diametral pitch 3.175 (8 module) 4

36、(6.35 module)Pitch diameter 41.874” 31.243”Normal pressure angle 20 degrees 20 degreesNumber of teeth 129 113Helix angle 14 degrees 25.285 degreesInterference on diameter/bore 0.004”/7.000” 0.005”/8.500”Figure 4. Sectors cut from half of each gearFigure 5. Finite element model of segment of half of

37、double helical fabricated gear9 11FTM11The ANSYS finite element code is used to evaluate stresses and deflections of these gears due to shrink fitbetween the shaft and gear. The academic version of ANSYS has a restriction on number of elements andnodes, which limits the size of part and the mesh den

38、sity for the model. Therefore, the model of the gear istaken as a symmetric segment from half of the gear. In order to simplify the problem, the helix angle waschanged to zero for the model. See Figure 6 through Figure 9.Figure 6. Solid gear von Mises stress distributionFigure 7. Fabricated gear von

39、 Mises stress distribution10 11FTM11Figure 8. Radial deflection of segment of half of solid gearFigure 9. Radial deflection of segment of half of double helical fabricated gearThe von Mises stresses are shown in the stress plots as they represent the stresses at any point withoutregardtodirectionoft

40、hestresstensors. ThevonMisesstressisindependentofthechangesindirectionofthestressatthetoothfillet,sinceitisafunctionofthedistortionenergyatapoint. ThevonMisesstress, svm,maybe evaluated using the three principal stresses, s1, s2, and s3.(20)svm= s1 s22+s2 s32+s3 s120.5wheresvmis von Mises stress, ps

41、i;s1is most positive principal stress, psi;11 11FTM11s2is intermediate value of principal stress, psi;s3is least positive principal stress, psi.These results show small stresses at the tooth flank due to shrink fitting of the gear onto the shaft. Cast andfabricated gear blanks may experience non-uni

42、form elastic distortion of the rim and non-uniform toothstresses at the bottom of the root due to the position and geometry of cutouts and ribs.Stresses due to the shrink fitting of the gear onto the shaft are evaluated by the finite element method. ThemaximumvonMisesstressesintherootoftheteethdueto

43、shrinkfittingofthegearontotheshaftareshowninFigure 10 and Figure 11, and are given in Table 4. These stresses include the influence of stress concentra-tion produced by changes in geometry. The maximum stresses occur in the roots of the teeth, where thestress is increased by the theoretical stress c

44、oncentration factor, Kt, 5. In the AGMA process of gear toothdesign,thefatiguestressconcentrationfactor,KfisappliedaspartoftheJ-Factorwhencalculatingthestressnumber per AGMA 918-A93 4. These shrink fitting induced stressesdecrease rapidlyas theyrise fromtherootanduptheflankofthetooth. Thefabricatedg

45、earshowshigherrootstressesandawidervariationacrossthegearfaceduetothevariationinelasticsupport. Inthisstudy,theinfluenceofshrinkfittingstress,ssf,onthederating factor are included.Table 4. Variation in von Mises stress across the root of teeth due to shrink fitting of gear ontoshaftSolid gear root s

46、tresses, psi Fabricated gear root stresses828 - 977 3627 - 7832Figure 10. Maximum von Mises stresses due to shrink fitting occur at root of tooth of fabricatedgear and peak at rib. Stresses include the effects of stress concentration due to tooth geometry12 11FTM11Figure 11. Maximum von Mises stress

47、es due to shrink fitting occur at root of tooth of solid gearand decrease at un-buttressed end. Stresses include the effects of stress concentration due totooth geometryMarine reversing main gear tooth derating factor when all cycles are reversal of travelThe reversing main gear teeth are subjected

48、to three different stress cycles. This section considers all lifecyclestobeduetovesselreversaltoestablishalowerlimitforthederatingfactor. Thenextsectionevaluatesthe derating factor for a combination of the three different stress cycles. The cycledue toreversing theves-sels travel direction may have

49、a relatively large number of cycles for applications like fire fighting tugs, shipdocking tugs, etc. A derating factor, Krev, is determined for the tooth stress cycling between smaxand- p smax,wherepistheratioofasterntorquetoaheadtorque. Therelationshipsbetweenmaximumstress,smax, minimum stress, smin, the derating factor, Krev, and the allowable stress number, sat, for the reversingcycle are:(21)smax= Krevsat(22)smin= pKrevsatwherep is ratio of a

copyright@ 2008-2019 麦多课文库(www.mydoc123.com)网站版权所有
备案/许可证编号:苏ICP备17064731号-1