ImageVerifierCode 换一换
格式:PDF , 页数:8 ,大小:728.22KB ,
资源ID:454535      下载积分:10000 积分
快捷下载
登录下载
邮箱/手机:
温馨提示:
快捷下载时,用户名和密码都是您填写的邮箱或者手机号,方便查询和重复下载(系统自动生成)。 如填写123,账号就是123,密码也是123。
特别说明:
请自助下载,系统不会自动发送文件的哦; 如果您已付费,想二次下载,请登录后访问:我的下载记录
支付方式: 支付宝扫码支付 微信扫码支付   
验证码:   换一换

加入VIP,免费下载
 

温馨提示:由于个人手机设置不同,如果发现不能下载,请复制以下地址【http://www.mydoc123.com/d-454535.html】到电脑端继续下载(重复下载不扣费)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: 微信登录  

下载须知

1: 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。
2: 试题试卷类文档,如果标题没有明确说明有答案则都视为没有答案,请知晓。
3: 文件的所有权益归上传用户所有。
4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
5. 本站仅提供交流平台,并不能对任何下载内容负责。
6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

版权提示 | 免责声明

本文(ASHRAE AN-04-2-1-2004 Vibration Isolation Harmonic and Seismic Forcing Using the Wilson Theta Method《隔振 被迫使用威尔逊太塔 法谐波和地震》.pdf)为本站会员(bowdiet140)主动上传,麦多课文库仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知麦多课文库(发送邮件至master@mydoc123.com或直接QQ联系客服),我们立即给予删除!

ASHRAE AN-04-2-1-2004 Vibration Isolation Harmonic and Seismic Forcing Using the Wilson Theta Method《隔振 被迫使用威尔逊太塔 法谐波和地震》.pdf

1、AN-04-2-1 Vibration Isolation: Harmonic and Seismic Forcing Using the Wilson Theta Method James A. Carlson, P.E. Associate Member ASHRAE Joseph Turner, Ph.D. ABSTRACT It is well known that equipment can causeunwantedvibra- tions in buildings. Springs have been used to isolate these vibrations and re

2、duce transmitted forces to building struc- tures. For simple vertical harmonic motion and free vibration, theproblem is easily evaluated using simple charts andjgures. Evaluation of spring-isolated equipment responding to earth- quakes is not simple. A numerical method is included to eval- uate resp

3、onse of equipment to earthquakes and harmonic forcing functions. Conjguration of equipment on springs is simplijied for numerical analysis. A simplijied approach and associated equations of motion can be developed to evaluate the response of the equipment with vertical and horizontal forcing functio

4、ns. Response of spring isolation in the vertical direction is based on the vertical forcing function acting on the center of mass and results in the translation of the total mass (up and down). Horizontal forcing functions result in a change in the angle around the center of mass. Ifthe mass of the

5、equip- ment is ofset from the center of mass, then the vertical and angular responses are coupled. Resulting tension and compression forces at the spring can be directly related to the center of mass vertical and rotational displacements and velocities. Results of this numerical method may be used t

6、o vertfi simplijied methods. INTRODUCTION Dynamic response of equipment to earthquake ground motion is becoming an active topic in the HVAC industry. Code requirements and equipment failures during recent earthquakes drive this growing attention. Code requirements focus on the seismic evaluation of

7、the anchorage and opera- tional effects in a very simple format. New building codes have been enhanced and are adopting more stringent requirements for both when to apply a seismic restraint design and increas- ing the earthquake forces applied to equipment. In some cases, the code requirements may

8、also require a shake table to prove operability. But for most code design considerations, the seis- mic restraint andlor anchorage is the only concern. For anchorage, the International Building Code (ICC 2000) endorses a static analysis, but will allow computational methods. A simplified static anal

9、ysis for calculating earth- quake forces acting on anchor bolts has been developed by ASHRAE for anchor bolt selection. But these equations are limited to very simple installations and only look at the peak response and estimated anchor bolt forces (tension, compres- sion, and shear) based on a stat

10、ic analysis and spring acceler- ation multipliers. Finite-element analysis programs have been used to look at more complex installations. These approaches also have drawbacks for the typical HVAC design engineer selecting spring isolators and anchorage systems. Finite-element programs are very compl

11、ex and are time consuming. Simpli- fied static analysis of complex systems may be too simple with unreasonable assumptions and results. One other analysis method includes calculating or measuring the impulse response and solving by convolution. This paper looks at a rigorous implicit evaluation of s

12、pring-isolated equipment that can be employed to evaluate simple and complex installation response to any input forcing functions. Several different input excitation functions are evaluated. Harmonic forcing functions (sine waves) are applied with frequencies from 1 to 30 Hz in the vertical, horizon

13、tal, and a combination of both. The seismic forcing function used for demonstration of the methodology is in terms of acceleration James A. Carlson is with the Omaha Public Power District, Fort Calhoun, Nebraska. Joseph Turner is at the University ofNebraska, Lincoln. 02004 ASHRAE. 321 tvg L 63 X t

14、Figure 1 Simple spring-isolated equipment mass Figure 2 Free body diagram of spring-isolated equipment. representation. using the El Centro earthquake data (Donea 1980). Future evaluations can be made with input excitations developed from earthquake peak response spectrum as defined in the building

15、codes. Design engineers can gain insight into the resultant forces at the spring and anchorage by looking at the system response. SPRI NG-ISOLATED EQUIPMENT Spring-isolated equipment is simplified for the analysis. A simple configuration for equipment is two masses resting on springs and dashpots (s

16、nubbers) and attached to the ground. The forcing functions (horizontal and vertical accelerations) are applied at the ground and represent forces generated by an earthquake. Equations of motion can be developed for this system. Structural engineers, looking at buildings, have already derived similar

17、 equations of motion. But buildings are uniform with the center of mass very near the center of the building. For equipment, the equations of motion are compli- cated by offset centers of mass. Figure 1 shows a typical instal- lation with springs mounted at the comers. The total mass is separated in

18、to two masses. The first mass is for the equipment elevated above the base by some height (hcg). The second mass represents a structural base. For equipment installed without a base, the base mass is simply zero for this analysis. The earthquake accelerations acting on the ground are represented by

19、v, and h, as seen in Figure 2. Intuitively, the horizontal oscillating forcing function will induce a rocking motion or a change in the angle defection of spring. The vertical acceleration will cause a translation of the total mass. The system selected to represent the typical equipment isolation sy

20、stem contains some information about the equip- ment and inherent features. These features include the stiff- ness (K,) and the damping coefficient (Ce) of the equipment in response to the horizontal forcing functions as shown in Figure 1. Damping coefficients for the equipment are typically assumed

21、 to be 5%. For this analysis the equipment effect and x motion are expected to be small and have an insignificant effect on the total mass translation and rocking motion. Future work will look at the stiffness and damping effects of the equipment. This work is looking at the motion at the springs an

22、d resulting spring compression and tension forces. Devel- opment of the free body diagram is completed without the equipment stiffness and damping. From Figure 2, the free body diagram, equations of motion (EOM) may be developed. SYSTEM RELATIONSHIPS There are several relationships that are used in

23、the devel- opment of the EOM. Inputs to the equations of motion use relationships of the displacement and mass as identified by the coordinate system selected. If there is an offset of the equip- ment mass as previously discussed, the center of mass of the system will not coincide with the equipment

24、 mass. This equip- ment mass offset is defined as a vector rAc as shown in Figure 2. Vector rAc is a simple summation problem determined by the relationship as shown in Equation 1. the base due to the equipment mass (M) and not the total mass (M+m). The horizontal force acts on the mass of the base

25、(m) (1) IMb + mL/4 M+ m b- ErAiMi - rAc = - but will be assumed to result only in a shear force acting on the CMi ASHRAE Transactions: Symposia 322 Equations of motion are defined in terms of the angular displacement (a) and the translation of the equipment in the vertical direction (x) at the cente

26、r of mass. The relative motion at the springs can be determined from the motion at the center of mass as defined by x and a as shown in Equations 2 and 3. xl = x-aa-rACa = x-(a+rAC)a, (2) x2 = x+ba-rAca = x+(b+rAc)a. (3) The relative velocity at the spring is simply the derivative of Equations 2 and

27、 3. i, = i-aa-rACa = i-(a+rAC)a, (4) i, = x+ba-rACa = X+(b+rAC)a. (5) The displacement and velocity of the springs that are determined from Equations 2,3,4, and 5 are used to calculate the transmitted forces (transmissibility) at the springs in tension and compression. The response at the spring is

28、one of the important results of this analysis needed to complete the anchorage design, A second important result for this analysis is the effect of damping on the system. Displacement of the spring will increase for weaker spring constants but decrease with increased damping. Displacement of the spr

29、ing may reach a maximum height where the spring is stretched beyond the design of the isolator. The displacement may also reach a minimum height and the solid length of the spring, causing a potential failure of the isolator. Typical spring constants are selected based on undamped vertical motion to

30、 reduce the transmitted forces to the building structure. This evaluation can look at the total displacement as well as the transmitted forces. Damping will reduce the total displacement of the spring without detrimentally increasing the transmissibility. The damping used in this analysis is a visco

31、us type damp- ing. Actual damping will be frictional based on the total force acting normal to the spring. The friction force can be calcu- lated by multiplying the total mass times the horizontal earth- quake acceleration times a friction factor (p) of steel to rubber. This fnctional force is a bet

32、ter assumption compared to viscous damping. However, the actual system will have a combination of both frictional and viscous type damping. A less rigorous and simplified approach is to assume the damp- ing is viscous with some damping coefficient (4). The damp- ing coefficient for equipment is usua

33、lly assumed to be 0.05 (5%). The results are acceptable when using viscous damping to see magnitudes and system response. Friction damping evaluations will be considered in future work. The mass moment of inertia of the system is used in the solution for the system rotation when summing the moments.

34、 The mass moment of inertia can be calculated by the relation- ships of the mass and their offsets added to the mass moment of the base. The total mass moment of inertia for this scheme is given by Equation 6. 2 2 I, = Z, + Mh, + mrAC In Equation 6, Io is the mass moment of the base. The example use

35、d in this paper assumes the base is a solid bar. For simplicity, the center of the bar mass is assumed to be at the mass center of the system. The mass of the equipment (M) and the mass of the base (m) are simply added for the total mass acting in the vertical direction. my = M+m (7) EQUATIONS OF MO

36、TION The previous relative relationships are inputs into the equations of motion for this two degrees of freedom system (2DOF). To solve for the motion, two equations are required. The first equation is obtained by summing forces in the verti- cal direction. The result is CF, = m$, ,(t. m,-kln - (a

37、+ rAc). a - c,x- (a + rAc). b, = 3/r;b2 = 2b1;b, = 2;b, = 2;b5 = t/2. (22) The incremental displacement is substituted into Equa- tion 17 to obtain the acceleration at r = t + O.At and directly plugged into Equations 12,13, and 14 for z = t + At. The final result for each incremental time step is gi

38、ven by where 2 b, = bO/;b7 = -b2/0;b8 = 1 - 3/0;b9 = At/2;bl0 = At /6. (26) Equations 2 1 23,24, and 25 only are required to be solved for any system. As in the seismic restraint design for spring- isolated equipment, the solution can be easily programmed on a spreadsheet. SOLUTION OF THE SPRING-ISO

39、LATED EQUIPMENT An example is used to illustrate this numerical solution. Consider a fan (1000 lb) with dimensions as given in Table 1 and selected so that the center of mass corresponds to the equipment mass center. The result is two uncoupled equations of motion where M, C, and K are identified in

40、 Equation 27. The vertical forcing function acts on the translation of the equip- ment and the horizontal forcing function acts on the rotation of the equipment base. For this example the equilibrium displacement is 0.75 inch as the 1000 pounds (lb) displace two springs with a 667 iblin. spring cons

41、tant. Input data for the calculation spreadsheet for analysis is shown in Table 1. The matrix form of the example given in Equation 27: M= The complete solution for this example of the spring- isolated fan is a very large spreadsheet. The actual table has Table 1. System Parameters Physical Dimensio

42、ns M= 2.33 Slugs m = 0.26 Slugs mt = 2.59 Slugs xes = 0.75 inches Icg = 34.1 slugs-in.2 Hcg = 35 inches L = 40 inches b = 20 inches 6 = 0.1 (damping coefficient) dt = 0.02 seconds e= 1.0 Wilson Theta Factors bo = 15000 b, = 150 b, = 2 b, = 2 b, = 300 b5 = 0.01 b6 = 15000 b7 = -300 b, = -2 b, = 0.01

43、bin = 6.667E-05 ASHRAE Transactions: Symposia 325 ._ Spring Deflection O 15 - 0.10 kb- Figure 4 Deflection ofthe springs. over 2500 time steps. Figure 4 is the total response of the equipment over the time history lasting 53 seconds. The maxi- mum displacement is O. 15 in. Since the equilibrium disp

44、lace- ment is 0.75 in., the response of this damped equipment is well within the capability of the spring. The equivalent acceleration of the El Centro earthquake is approximately 0.3 19 gs. The equivalent g-level of the earthquake is used in the static anal- ysis. This earthquake is minor compared

45、to the code require- ments. Higher accelerations and resultant forces would be expected for an acceptable evaluation to meet code require- ments. The resultant spring forces can be calculated from the transmissibility as defined by The transmissibility is positive where the spring is in tension or n

46、egative where the spring is in compression. The maximum forces with a viscous damping coefficient of 0.1% at spring 1 are 159 lb in tension and 106 lb in Compression. The maximum forces at spring 2 are 258 lb in tension and 386 lb in compression. The maximum forces with a viscous damping coefficient

47、 of 0.3% at spring 1 are 155 lb in tension and 1 14 lb in compression. The maximum forces at spring 2 are 27 1 lb in tension and 385 lb in compression. A comparison is made with the static analysis. Based on the International Building Code, the maximum horizontal force developed by an earthquake wou

48、ld be defined by Equa- tion 29. I Fp = (0.4.a .SD,.W)l(1+2$ RP P = (0.4.2.5 .0.319. IOOo)( 1 + 2 .3 = 127.6 . (29) Earhquake Acceleration E .- Z. 50 f -50 50 Figure 5 Acceleration time history of the El Centro earthquake. I Earthquake Velocity Profile Figure 6 Velocity of the ground during the El Ce

49、ntro earthquake. The compression and tension of the spring-isolated equipment are calculated using the ASHRAE guideline as defined in Equation 30, where Fpv = FJ3. I Fh) F eq- 2LI - 4 T,C = F iuR+Lv T, C = Feqk(L 127.6.35 + -) 127.6/3 = , 40 2 The static analysis, as defined by the code, results in a tension and compression about equilibrium of h133 lb. The analysis completed using the numerical method resulted in higher forces than would be allowed by a static analysis. The tension for both analyses is within 10%. But the compression allowed by code is approximately one-th

copyright@ 2008-2019 麦多课文库(www.mydoc123.com)网站版权所有
备案/许可证编号:苏ICP备17064731号-1