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本文([外语类试卷]GRE(QUANTITATIVE)练习试卷3及答案与解析.doc)为本站会员(orderah291)主动上传,麦多课文库仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知麦多课文库(发送邮件至master@mydoc123.com或直接QQ联系客服),我们立即给予删除!

[外语类试卷]GRE(QUANTITATIVE)练习试卷3及答案与解析.doc

1、GRE( QUANTITATIVE)练习试卷 3及答案与解析 1 What is the hypotenuse of a right triangle with a base of 9 cm and an area of 54 cm2? 2 What is the area of a circle with a circumference of 14 inches? 3 If one of the angles of a parallelogram measures 35, what is the sum of the remaining angles? 4 A trapezoid has o

2、ne base of 8 ft, a height of 3 ft, and an area of 30 ft2. What is the length of the other base? 5 A polygon with four sides and four right angles has one side of 6 mm. If the area of the polygon is 42 mm2, would the polygon be considered a square or a rectangle? GRE( QUANTITATIVE)练习试卷 3答案与解析 1 【正确答案

3、】 The area of a triangle and the length of one of the legs of a right triangle are given. However, you need the length of both legs to use the Pythagorean theorem to determine the hypotenuse. Since you have the area, start there. For a triangle, . You are given the base and area, so solve for the he

4、ight: Now you know the lengths of the two legs of the right triangle and can use the Pythagorean theorem (a2+b2=c2) to determine the hypotenuse: 92+122=c2 81+144=c2 225=c2 15=c. The hypotenuse is 15 cm. 2 【正确答案】 The equation for the area of a circle is A=r2. The equation for the circumference of a c

5、ircle is C=2r. Since you are given the circumference, you can use that to find the radius, r, and then use the radius to find the area: 14=2r 14=2r r=7 Now substitute r into the equation for area: Area=(72) Area=49 3 【正确答案】 A parallelograms angles add up to 360. So simply subtract 35 from 360: 360-3

6、5=325. 4 【正确答案】 The equation for the area of a trapezoid is Substitute the given variables into the equation and solve for the missing base: 5 【正确答案】 A square is a special kind of rectangle. All of its sides are equal in length. Since the area of a rectangle is area =1w, the area of a square would be area=s2 (side squared) because length and width are equal. For this problem, the given side is 6 mm. If the figure were a square, the area would be 36 mm2. However, the area is said to be 42 mm2. Therefore the shape is a rectangle and not a square.

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