ATIS 0700361-2015 Wideband General Packet Radio Service (WGPRS) Packet-Data Service- High Speed (HS) Indoor Physical Layer.pdf

1、 ATIS-0700361 ATIS Standard on - WIDEBAND GENERAL PACKET RADIO SERVICE (WGPRS) PACKET-DATA SERVICE HIGH SPEED (HS) INDOOR PHYSICAL LAYER As a leading technology and solutions development organization, the Alliance for Telecommunications Industry Solutions (ATIS) brings together the top global ICT co

2、mpanies to advance the industrys most pressing business priorities. ATIS nearly 200 member companies are currently working to address the All-IP transition, network functions virtualization, big data analytics, cloud services, device solutions, emergency services, M2M, cyber security, network evolut

3、ion, quality of service, billing support, operations, and much more. These priorities follow a fast-track development lifecycle from design and innovation through standards, specifications, requirements, business use cases, software toolkits, open source solutions, and interoperability testing. ATIS

4、 is accredited by the American National Standards Institute (ANSI). The organization is the North American Organizational Partner for the 3rd Generation Partnership Project (3GPP), a founding Partner of the oneM2M global initiative, a member of and major U.S. contributor to the International Telecom

5、munication Union (ITU), as well as a member of the Inter-American Telecommunication Commission (CITEL). For more information, visit www.atis.org. Notice of Disclaimer the description in the time domain is addressed in subclause 4.5. 4.2 Bursts 4.2.1 General A burst is a period of RF carrier, which i

6、s modulated by a data stream. A burst therefore represents the physical content of a timeslot. 4.2.2 Types of Burst and ii) A TDMA frame number sequence. The physical channels where the TDMA frame number sequence is 0,1. . FN_MAX (where FN_MAX is defined in subclause 3.3.3) are called basic wideband

7、 physical channels. 4.6 Parameters for Channel Definition ii) The TN; iii) The MA; iv) The type of logical channel. ATIS-0700361 10 5 Mapping of Logical Channels onto Physical Channels 5.1 General The detailed mapping of logical channels onto physical channels is defined in the following subclauses.

8、 Subclause 5.2 defines the mapping from TDMA FN to RFCH. Subclause 5.3 defines the mapping of the physical channel onto TDMA frame number. 5.2 Mapping in Frequency of Logical Channels onto Physical Channels 5.2.1 General The parameters used in the function which maps TDMA frame number onto radio fre

9、quency channel are defined in subclause 5.2.2. 5.2.2 Parameters The following parameters are required in the mapping from TDMA frame number to radio frequency channel for a given assigned channel. General parameters of the BTS, specific to one BTS, and broadcast in the broadcast channel and WSCH: i)

10、 CA: Cell allocation of radio frequency channels. ii) FN: TDMA frame number, broadcast in the WSCH, in form T1, T2, T3. Specific parameters of the channel, defined in the channel assignment message: i) MA: Mobile allocation of radio frequency channels, defines the radio frequency channel. 5.3 Mappin

11、g in Time of Logical Packet Channels onto Physical Channels 5.3.1 General A physical channel allocated to carry packet logical channels is called a packet switched channel (PDCH). A PDCH shall carry packet logical channels only. Packet switched logical channels are mapped dynamically onto a 52-multi

12、frame. The 52-multiframe consists of 12 blocks of 4 consecutive frames and 4 idle frames. A block allocated to a given logical channel comprises of one radio block. The type of channel may vary on a block by block basis. Table 5.1 below indicates the frame numbers for each of the blocks (B0.B11) tra

13、nsmitted in the multiframe. In case of wideband long bursts with channel coding WGPRS Modulation and Coding Scheme (WMCS)-2 and WMCS-4 one burst forms one radio block, and each frame can be referred to as a subblock of the bigger block (B0.0, B0.1, B0.2, B0.3, B1.0, B1.1 B11.3). In the downlink dire

14、ction, the logical channel type shall be indicated by the message type contained in the block header part. The frequency correction channel and synchronization channel will be always transmitted after each other. Transmission takes place twice during each idle frame. First pair of bursts is sent in

15、time slots 0 and 1, the second pair on time slots 32 and 33. ATIS-0700361 11 Table 5.1 Allowed channel and time-slot assignments Channel designation Allowable time-slot assignment Allowable RF channel assignment Burst type Radio block to TDMA frame mapping WPTCH, WPACCH 0, 1, 2, ., 63 C0.Cn WSB WLB

16、(WMCS1and 3) B0(0.3), B1(4.7), B2(8.11), B3(13.16), B4(17.20), B5(2124), B6(26.29), B7(30.33), B8(34.37), B9(39.42), B10(43.46), B11(47.50) WPTCH 0, 4, 8, , 60 C0.Cn WLB (WMCS2and 4) B0.0(0), B0.1(1), B0.2 (2), B0.3(3), B1.0(4), B1.1(5), B1.2(6), B1.3(7), B11.0(47), B11.1(48), B11.2(49), B11.3(50) W

17、FCCH 0, 32 C0Cn WFB (12), (24), (36), (48) WSCH 1, 33 C0Cn WSYB (12), (24), (36), (48) 52 TDMA Frames B0 B1 B2 B3 I B4 B5 B6 B7 I B8 B9 B10 B11 II = Idle frame (WSCH, WFCCH), B0 . B11 = Radio Blocks Figure 5.1 52 multiframe for PTCH 5.3.2 Mapping of Uplink Packet Traffic Channels (WPTCH/U Kx gives t

18、he amount of bits in one block, where x refers to the data type; n is used for numbering of delivered data blocks where; N marks a certain data block; B is used for numbering of bursts or blocks where; B0 marks the first burst or block carrying bits from the data block with n = 0 (first data block i

19、n the transmission). Data bits delivered to the encoding unit: d(k) for k = 0,1,.,Kd-1 Code identifying the used coding scheme (for packet switched channels only): ATIS-0700361 13 q(k) for k = 0,1,., 7 Data bits after the first encoding step (block code, cyclic code): u(k) for k = 0,1,.,Ku-1 Data pu

20、t into the shift register of the convolutional code and calculated from the data bits u(k) and the feedback bits in recursive systematic convolutional codes: r(k) for k= 0,1,., Kr-1 Data after the second encoding step (convolutional code): c(n,k) or c(k) for k = 0,1,.,Kc-1 n = 0,1,.,N,N+1,. Interlea

21、ved data bits: i(B,k) for k = 0,1,.,Ki-1 B = B0, B0+1, Bits in one burst: e(B,k) for k = 0,1,176 B = B0,B0+1,. 6.3 Wideband Modulation u(k) = 0 for k 0 The code is punctured depending on the value of the puncturing scheme indicator field as defined in ATIS-0700362. Two puncturing schemes named P1 or

22、 P2 are applied in such a way that the following coded bits: The result is a block of 456 coded bits dc(0),dc(1),.,dc(455). 6.3.6 Data Coding for Long Bursts a) Parity bits: Twelve data parity bits p(0),p(1),.,p(11) are defined in such a way that in GF(2) the binary polynomial: d(31)D1345 +.+ d(1364

23、)D12 + p(0)D11 +.+ p(11), when divided by: D12 + D11 + D10 + D8 + D5 + D4 + 1, yields a remainder equal to: D11 + D10 + D9 + D8 + D7 + D6 + D5 + D4 + D3 + D2 + D + 1. b) Tail bits: Six tail bits equal to 0 are added to the information and parity bits, the result being a block of 1352 bits u(0),u(1),

24、.,u(1351): u(k) = d(k+31) for k = 0,1,.,1333 u(k) = p(k-1334) for k = 1334,1335,.,1345 u(k) = 0 for k = 1346,1347,1351 (tail bits) c) Convolutional encoder: The block of 1352 bits u(0),u(1),.,u(1351) is encoded with the 1/3 rate convolutional mother code defined by the polynomials: P1 P2 C(2+3j) for

25、 j = 0,1,.,227 are not transmittedC(1+3j), for j = 0,1,.,227 are not transmittedATIS-0700361 16 G4 = 1 + D2 + D3 + D5 + D6 G7 = 1 + D + D2 + D3 + D6 G5 = 1 + D + D4 + D6This results in a block of 4056 coded bits: C(0),C(1),.,C(4055) defined by: C(3k) = u(k) + u(k-2) + u(k-3) + u(k-5) + u(k-6) C(3k+1

26、) = u(k) + u(k-1) + u(k-2) + u(k-3) + u(k-6) C(3k+2) = u(k) + u(k-1) + u(k-4) + u(k-6) for k = 0,1,.,1351; u(k) = 0 for k 0 The code is punctured depending on the value of the Puncturing scheme indicator field as defined in ATIS-0700362. Two puncturing schemes named P1 or P2 are applied in such a wa

27、y that the following coded bits: The result is a block of 2704 coded bits dc(0),dc(1),.,dc(2703). 6.3.7 Interleaving for Short Bursts The USF, header and data are put together as one entity as described by the following rule: c(2*k+1) = u(k) for k = 0, 1, , 11 c(2*k) = hc(k) for k = 0, 1, , 11 c(k)

28、= hc(k-24) for k = 24, 25, ., 119 c(k) = dc(k-120) for k = 120, 121, ., 575 The resulting block is interleaved according to the following rule: i(Bh,j) = c(k), for k = Bh+8*j Bh = 0 7 j = 0 71 6.3.8 Interleaving for Long Bursts The USF, header and data are put together as one entity as described by

29、the following rule: c(k) = u(k) for k = 0, 1, , 11 c(2*k) = hc(k) for k = 0, 1, , 11 c(k) = hc(k-24) for k = 24, 25, ., 119 c(k) = dc(k-120) for k = 120, 121, ., 2823 The resulting block is interleaved according to the following rule: i(Bh,j) = c(k), for k = Bh+8*j Bh = 0 7 j = 0 352 P1 P2 C(2+3j) f

30、or j = 0,1,.,1351 are not transmittedC(1+3j), for j = 0,1,.,1351 are not transmittedATIS-0700361 17 6.3.9 Mapping on a Short Burst The mapping is given by the rule: e(B0+B,j) = i(Bh,j) and e(B0+B,72+j) = i(Bh+1,j) for j = 0,1,.,71 Bh = 0 ,2, 4, 6 B = int(Bh /2) 6.3.10 Mapping on a Long Burst The map

31、ping is given by the rule: e(B,j) = i(Bh,j) and e(B,353+j) = i(Bh+1,j) for j = 0,1,.,352 Bh = 0 ,2, 4, 6 B = int(Bh /2) 6.4 Wideband Modulation u(k) = 0 for k 0 The code is punctured depending on the value of the puncturing scheme indicator field as defined in ATIS-0700362. Two puncturing schemes na

32、med P1 or P2 are applied in such a way that the following coded bits: The result is a block of 456 coded bits dc(0),dc(1),.,dc(455). 6.4.5 Data Coding for Long Bursts a) Parity bits: Twelve data parity bits p(0),p(1),.,p(11) are defined in such a way that in GF(2) the binary polynomial: d(31)D1345 +

33、.+ d(1364)D12 + p(0)D11 +.+ p(11), when divided by: D12 + D11 + D10 + D8 + D5 + D4 + 1, yields a remainder equal to: D11 + D10 + D9 + D8 + D7 + D6 + D5 + D4 + D3 + D2 + D + 1. b) Tail bits: Six tail bits equal to 0 are added to the information and parity bits, the result being a block of 1352 bits u

34、(0),u(1),.,u(1351): P1 P2 C(2+3j) for j = 3, 4, 5, ., 227 are not transmittedC(1+3j), for j = 3, 4, 5, ., 227 are not transmittedATIS-0700361 19 u(k) = d(k+31) for k = 0,1,.,1333 u(k) = p(k-1334) for k = 1334,1335,.,1345 u(k) = 0 for k = 1346,1347,1351 (tail bits) c) Convolutional encoder: The block

35、 of 1352 bits u(0),u(1),.,u(1351) is encoded with the 1/3 rate convolutional mother code defined by the polynomials: G4 = 1 + D2 + D3 + D5 + D6 G7 = 1 + D + D2 + D3 + D6 G5 = 1 + D + D4 + D6This results in a block of 4056 coded bits: C(0),C(1),.,C(4055) defined by: C(3k) = u(k) + u(k-2) + u(k-3) + u

36、(k-5) + u(k-6) C(3k+1) = u(k) + u(k-1) + u(k-2) + u(k-3) + u(k-6) C(3k+2) = u(k) + u(k-1) + u(k-4) + u(k-6) for k = 0,1,.,1351; u(k) = 0 for k 0 The code is punctured depending on the value of the Puncturing scheme indicator field as defined in ATIS-0700362. Two puncturing schemes named P1 or P2 are

37、 applied in such a way that the following coded bits: The result is a block of 2704 coded bits dc(0),dc(1),.,dc(2703). 6.4.6 Interleaving for Short Bursts The header and data are put together as one entity as described by the following rule: c(k) = hc(k) for k = 0, 1, ., 116 c(k) = dc(k-117) for k =

38、 117, 118, ., 575 The resulting block is interleaved according to the following rule: i(Bh,j) = c(k), for k = Bh+8*j Bh = 0 7 j = 0 71 6.4.7 Interleaving for Long Bursts The header and data are put together as one entity as described by the following rule: c(k) = hc(k) for k = 0, 1, ., 116 c(k) = dc

39、(k-117) for k = 117, 118, ., 2823 The resulting block is interleaved according to the following rule: i(Bh,j) = c(k), for k = Bh+8*j Bh = 0 7 j = 0 352 6.4.8 Mapping on a Short Burst The mapping is done as in subclause 6.3.9. P1 P2 C(2+3j) for j = 3 ,4 ,5, ., 1351 are not transmittedC(1+3j), for j =

40、 3, 4, 5,., 1351 are not transmittedATIS-0700361 20 6.4.9 Mapping on a Long Burst The mapping is done as in subclause 6.3.10. 6.5 Wideband Modulation u(k) = 0 for k 0 The code is punctured depending on the value of the puncturing scheme indicator field as defined in ATIS-0700362. The puncturing sche

41、me named P1, P2 or P3 is applied in such a way that the following coded bits: The result is a block of 456 coded bits dc(0),dc(1),.,dc(455). 6.5.6 Data Coding for Long Bursts a) Parity bits: Twelve data parity bits p(0),p(1),.,p(11) are defined in such a way that in GF(2) the binary polynomial: d(31

42、)D579 +.+ d(598)D12 + p(0)D11 +.+ p(11), when divided by: D12 + D11 + D10 + D8 + D5 + D4 + 1, yields a remainder equal to: D11 + D10 + D9 + D8 + D7 + D6 + D5 + D4 + D3 + D2 + D + 1. b) Tail bits: Six tail bits equal to 0 are added to the information and parity bits, the result being a block of 586 b

43、its u(0),u(1),.,u(585): u(k) = d(k+31) for k = 0, 1, ., 567 u(k) = p(k-568) for k = 568 ,569 ,., 579 u(k) = 0 for k = 580, 581, , 585 (tail bits) c) Convolutional encoder: The block of 586 bits u(0),u(1),.,u(585) is encoded with the 1/3 rate convolutional mother code defined by the polynomials: G4 =

44、 1 + D2 + D3 + D5 + D6 G7 = 1 + D + D2 + D3 + D6 G5 = 1 + D + D4 + D6This results in a block of 1758 coded bits: C(0),C(1),.,C(1757) defined by: C(3k) = u(k) + u(k-2) + u(k-3) + u(k-5) + u(k-6) C(3k+1) = u(k) + u(k-1) + u(k-2) + u(k-3) + u(k-6) C(3k+2) = u(k) + u(k-1) + u(k-4) + u(k-6) for k = 0 ,1

45、,., 1757, u(k) = 0 for k 0 The code is punctured depending on the value of the puncturing scheme indicator field as defined in ATIS-0700362. The puncturing scheme named P1, P2 or P3 is applied in such a way that the following coded bits: P1 P2 P3 C(3j) for j = 0,1,., 455 are transmitted C(1+3j), for

46、 j = 0,1,.,455 are transmittedC(2+3j) for j = 0,1,.,455 are transmittedATIS-0700361 22 The result is a block of 586 coded bits dc(0),dc(1),.,dc(585). 6.5.7 Interleaving for Short Bursts Interleaving is done as in subclause 6.3.7. 6.5.8 Interleaving for Long Bursts The USF, header, and data are put t

47、ogether as one entity as described by the following rule: c(k) = u(l) for k = 353, 317, 281, 245, 209, 173, 137, 101, 65, 29, 699, 663 when l = 0, 1, , 11 c(k) = hc(k) for k = 0, 1, 28 c(k) = hc(k-1) for k = 30, 31, 64 c(k) = hc(k-2) for k = 66, 67, 100 c(k) = hc(k-3) for k = 102, 103, 110 c(k) = dc

48、(k-111) for k = 111, 112, 136 c(k) = dc(k-112) for k = 138, 139, 172 c(k) = dc(k-113) for k = 174, 175, 208 c(k) = dc(k-114) for k = 210, 211, 244 c(k) = dc(k-115) for k = 246, 247, 280 c(k) = dc(k-116) for k = 282, 283, 316 c(k) = dc(k-117) for k = 318, 319, 352 c(k) = dc(k-118) for k = 354, 355, 6

49、62 c(k) = dc(k-119) for k = 664, 665, 698 c(k) = dc(k-120) for k = 700, 701, 705 The resulting block is interleaved according to the following rule: i(B,j) = c(n, k) for k = 0, 1, , 705 n = 0, 1, , N, N+1, B = B0j = (49*k) mod 343 6.5.9 Mapping on a Short Burst Mapping is done as in subclause 6.3.9 6.5.10 Mapping on a Long Burst The mapping is given by the rule: e(B, j) = i(B,j) for j = 0,1,.,705 P1 P2 P3 C(3j) for j = 0,1,., 585 are transmitted