GOST EN 1108-2012 Roofing and hydraulic-insulating flexible bitumen-based materials Method for determination of form stability under cyclical temperature changes《屋面和液压绝缘柔性沥青基材料 周期性.pdf

1、 , () INTERSTATE COUNCIL FOR STANDARDIZATION, METROLOGY AND CERTIFICATION (ISC) EN 1108 2012 - (N 1108:1999, IDT) 2014 EN 11082012 II , 1.092 . 1.22009 . -, . , , , 1 - ( ) - , 4 2 465 3 - , - () ( 41 18 2012 .) : (IS 3166) 00497 (IS 3166) 00497 AZ - AM KG MD - RU UZ 4 N 1108:1999 Flexi-ble sheets f

2、or waterproofing Bitumen sheets for roof waterproofing Determination of form stability under cyclical temperature changes ( . - . ). 1.52001 ( 3.6). - , . (en). (IDT) 5 17 - 2013 . 2292- EN 11082012 - 01 2014 . 6 EN 11082012 III - , . () - - . , , 2014 -, - EN 11082012 IV , - , , - , . , - , - , , .

3、 EN 1108 2012 1 Roofing and hydraulic-insulating flexible bitumen-based materials. Method for determination of form stability under cyclical temperature changes 2014 07 01 1 - () ( -) - . () , . - - . - . , . 2 : ISO 5725:1986* Precision of test methods Determination of repeatability and reproducibi

4、lity for a standard test method by inter-laboratory tests ( - ) 3 : 3.1 (form stability): , - , . 4 , , , - - 10 . , - . 5 5.1 2000 1 . 5.2 2200300100 , (. 1), - 22 . 5.3 125 /3 40 . * IS 5725-2:1994. EN 11082012 2 5.4 , - 1 . 5.5 . 5.6 (, ), - (. 1). 5.7 (, , - , , . 1). 5.8 (, ) - 0,1 . 5.9 - 70 (

5、 - 8). 5.10 : ( ) 80 100 20/10 35/10 . 5.11 . 6 - . , , 2000100 300 , . , . 24 (23 2) -. ; ; ; 1 (A B); 2 (); 3 ; 4 - 1 EN 11082012 3 7 7.1 , - (. 1). -. 7.2 7.3; 40 . 7.2 - 40 ; , 180 200 , . - . 40 . 7.3 - ( 1,5 /2), . 40 ; , , - . . 40 . 7.4 , 1. - (. 1). , . - (. 1). . (23 2) 24 . 8 : - LA LB 1

6、(. 1); - - l1(0), l2(0), l3(0), l4(0) 0,1 (. 1). , , 10 - : 4 5 (70 2) ( ); 2 5 ; 4 5 (70 2) ( ); 14 15 . , -, 8 . - 70 1 . 30 . - . EN 11082012 4 , - . -. 22 . z ( 14- ) l1(z), l2(z), l3(z), l4(z). - . 9 , 9.1 z L, %, 100)()()( 21 AA L zlzlzL (1) 100)()()( 43 BB L zlzlzL (2) LA; LB ; l1(z), l2(z), l3(z), l4(z) l1, l2, l3, l4 z - l1(0), l2(0), l3(0), l4(0), , l1(z) l1(z) l1 (0). 0,01 %. (. 2) : - ( ) L(3); - Lmax; - L = Lmax L(3). L -