GOST R 50779 24-2005 Interpretation of statistical data Estimation of a median《统计数据的解释 中值估计》.pdf

1、 ISO 8595:1990Interpretation of statistical data Estimation of a median(MOD) 50779.24 2005( 8595:1990)22004/7, 1.092 - . 1.292 - . 1 125 , 42 3 - 31 2005 . 112-4 8595:1990 . . (ISO 8595:1990 Interpretation of statistical data Estimation of a median, MOD), , , . - 1.5 ( 3.6)5 - , -. , 2005 , - - 5077

2、9.242005II Interpretation of statistical data Estimation of a median 200507011 . - n . , , - ().2 : 50779.102000 ( 3534-193) . . ( 3534-1:1993, IDT) 50779.222005 ( 2602:1980) . - . ( 2602:1980 - . . , MOD)1 8595:1990 (ISO 8595:1990) - .2 , 1 , - , . (-), (). , , , - , .3 50779.10, :1 50779.242005( 8

3、595 : 1990) 3.1 k- n (k-th order statistic of a sample of size n): k- xk n , .xx xn .12c163c163c163c75 (1)3.2 (median of a continuous probabilitydistribution), M ( x,05): , F(M) = 0,5, (2) F (x) .4 , , , . , - . 50779.22. , k , - , , :PK knpnkppknk(;,) (),c61c61c230c232c231c246c248c247c45c451 (3) n

4、; , ; k , , n. , = 0,5, ( = k; n, 0,5) =nknc230c232c231c246c248c2472. (4)5 . - , , :-(n + 1)/2- , n ;- n/2-n/2 + 1- , n . ; - .6 6.1 - , ,TT12TT12c60 ;T1 2 .2 50779.242005 : T1, c165) ( c165, T2, 1 2 . , -, - . , , .6.2 - 1 c97/2 xk, xnkc45c431, k :niiknc230c232c231c231c246c248c247c247c163c61c45c45c

5、22901122c97 ; (5)niiknc230c232c231c231c246c248c247c247c62c61c45c45c22901122c97 . (6) c97 /2 c97. n 1. 1 k nn 0,95 0,99 0,95 0,9956789101112131415161718192021222324252627282930111222334445566677888991010110011112223334455566677888901112223334455566677888991000011112223334445556677788 0 , .3 50779.242

6、005 5c163nc16330 1 c97( ) k :Txk1c61,(7)Txnk21c61c45c438 xx xn, ,12c75 . n .6.3 n, 1, k , ynunc61c43c45c45,( ,)05 1 05 ,(9) k y, u , - uuc61c451 c97 ;uuc61c4512c97 . c97. k (10), 1 (9), n, - , 1:ynun uc61c43c45c43c45,( , , )05 1 05 0252, (10) k y.1 - . . - . , 24 ; , , :57,5; 77,8; 88,0; 96,9; 98,4;

7、 100,3; 100,8; 102,1; 103,3;103,4; 105,3; 105,4; 122,6; 139,3; 143,9; 148,0; 151,3;161,1*; 161,2*; 161,2*; 162,4*; 162,7*; 163,1*; 176,8*. - () )xx12 13c43 /2 = (105,4 + 122,6)/2 = 114. (11) - 0,95 : 1 n = 24 - k = 8, x8= 102,1, .2 34 , , . , , -:3; 4; 5; 6; 6; 7; 8; 8; 9; 9; 9; 10; 10; 11; 11; 11;

8、13; 13; 13; 13; 13;17; 17; 19; 19; 25; 29; 33; 42; 42; 52; 52*; 52*; 52*. - () xx17 18c43 /2 = (13 + 13)/2 = 13. (12) n 30 ; 0,95 -4 50779.242005ynunc61c43c45c45c6105 1 05,( ,) (13)c61c43c45 c45c610 5 34 1 1 645 34 0 5,( , ,)c61 12, 74;k y, ,k=12 x12= 10. , k , . :ynunc61c43c45c45c6105 1 05,( ,) (14

9、)c61c43c45 c45c610 5 34 1 1 960 34 0 5,( , ,)c61 11, 83, k = 11;nk+1=24 , xx11 24= 9, 19. (15)5 50779.242005 519.25:620.113:006.354 03.120.10 T59 : , , , , , . . . . 07.06.2005. 14.06.2005. 60c180841/8. . . . . . . 0,93. .-. . 0,50. 654 . . 366. C 1363. , 123995 , ., 4.www.gostinfo.ru infogostinfo.ru . . , 105062 , ., 6. 50779.242005