2019年春七年级数学下册第五章相交线与平行线5.2平行线及其判定5.2.2平行线的判定课件(新版)新人教版.pptx

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2019年春七年级数学下册第五章相交线与平行线5.2平行线及其判定5.2.2平行线的判定课件(新版)新人教版.pptx_第1页
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第五章 相交线与平行线,5.2 平行线及其判定,解:( 1 )bc.理由:ba,ca, 1=2=90,bc. ( 2 )规律:在同一平面内,如果两条直线同时垂直于一条直线,那么这两条直线平行.,解:A=C,B=D, B+C=D+A=180,ABCD. A=C,B=D, A+B=C+D=180,ADBC.,A.2=3 B.1=2 C.4=5 D.3=4,证明:1=2,ABCD. 3+4=180,CDEF,ABEF.,解:分8种情况讨论: ( 1 )如图1,BAD=45时,AD边与OB边平行; ( 2 )如图2,BAD=90+45=135时,AC边与OB平行; ( 3 )如图3,BAD=60+90=150时,DC边与AB边平行; ( 4 )如图4,BAD=135+30=165时,DC边与OB边平行; ( 5 )如图5,BAD=45-30=15时,DC边与OB边平行; ( 6 )如图6,BAD=15+90=105时,DC边与AO边平行; ( 7 )如图7,BAD=30时,DC边与AB边平行; ( 8 )如图8,BAD=30+45=75时,DC边与AO边平行.,

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