2019版高考数学二轮复习专题二函数与导数2.2.3函数与导数的应用专项练课件文.ppt

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1、2.3 函数与导数的应用专项练,-2-,1.函数y=f(x)在点x0处的导数是曲线y=f(x)在P(x0,f(x0)处的切线的斜率f(x0). 2.常用的求导方法,-3-,一、选择题,二、填空题,1.(2018全国卷1,文6)设函数f(x)=x3+(a-1)x2+ax,若f(x)为奇函数,则曲线y=f(x)在点(0,0)处的切线方程为( ) A.y=-2x B.y=-x C.y=2x D.y=x,答案,解析,-4-,一、选择题,二、填空题,2.若函数f(x)=kx-ln x在区间(1,+)内单调递增,则k的取值范围是( ) A.(-,-2 B.(-,-1 C.2,+) D.1,+),答案,解析

2、5-,一、选择题,二、填空题,3.(2018山东师大附中一模,文11)若f(x)=- x2+mln x在(1,+)是减函数,则m的取值范围是( ) A.1,+) B.(1,+) C.(-,1 D.(-,1),答案,解析,-6-,一、选择题,二、填空题,答案,解析,-7-,一、选择题,二、填空题,答案,解析,-8-,一、选择题,二、填空题,6.已知定义在R上的函数f(x)=ex+mx2-m(m0),当x1+x2=1时,不等式f(x1)+f(0)f(x2)+f(1)恒成立,则实数x1的取值范围是( ),答案,解析,-9-,一、选择题,二、填空题,7.(2018宁夏银川一中一模,文12)若函数f

3、x)=x3-3x在(a,6-a2)上有最小值,则实数a的取值范围是( ),答案,解析,-10-,一、选择题,二、填空题,答案,解析,-11-,一、选择题,二、填空题,9.设函数f(x)是奇函数f(x)(xR)的导函数,f(-1)=0,当x0时,xf(x)-f(x)0成立的x的取值范围是( ) A.(-,-1)(0,1) B.(-1,0)(1,+) C.(-,-1)(-1,0) D.(0,1)(1,+),答案,解析,-12-,一、选择题,二、填空题,10.(2018河南郑州三模,文11)已知函数f(x)=ax+x2-xln a,对任意的x1,x20,1,不等式|f(x1)-f(x2)|a-2恒

4、成立,则a的取值范围为( ) A.e2,+) B.e,+) C.2,e D.e,e2,答案,解析,-13-,一、选择题,二、填空题,答案,解析,-14-,一、选择题,二、填空题,答案,解析,-15-,一、选择题,二、填空题,13.(2018全国卷2,文13)曲线y=2ln x在点(1,0)处的切线方程为 .,答案,解析,-16-,一、选择题,二、填空题,14.(2018天津卷,文10)已知函数f(x)=exln x,f(x)为f(x)的导函数,则f(1)的值为 .,答案,解析,-17-,一、选择题,二、填空题,15.若函数f(x)=(x2-ax+a+1)ex(aN)在区间(1,3)只有1个极值点,则曲线f(x)在点(0,f(0)处切线的方程为 .,答案,解析,-18-,一、选择题,二、填空题,16.(2018江苏卷,11)若函数f(x)=2x3-ax2+1(aR)在(0,+)内有且只有一个零点,则f(x)在-1,1上的最大值与最小值的和为 .,答案,解析,

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