2018_2019学年七年级数学下册第三章整式的乘除3.6同底数幂的除法(一)练习(新版)浙教版.doc

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1、13.6 同底数幂的除法(一)A组1下列运算正确的是(C)A. a2a3 a6 B. 2 a3 b5 abC. a8a2 a6 D. ( a2b)2 a4b2计算: a3a_ a2_3计算:(4) 6(4) 3_64_4计算:(1)a10a2.【解】 原式 a102 a8.(2)( t)4( t)【解】 原式( t)3 t3.(3)( xy)5( xy)3.【解】 原式( xy)2 x2y2.(4)m5( m)2.【解】 原式 m5m2 m3.(5)(y2)3y3.【解】 原式 y6y3 y3.(6)(x y)7(x y)5.【解】 原式( x y)2 x22 xy y2.5计算:(1)( a

2、)7a3( a)2( a2)3.【解】 原式 a7a3a2( a6) a4a2( a6) a6( a6)1.(2)(3 a3)2a2.【解】 原式9 a6a29 a4.(3)(x3)2x2 x3( x)2( x)【解】 原式 x6x2 x5( x) x4 x40.6解方程:(1)26x2 8. (2)6 x(6) 3.【解】 (1) x2 826, x2 2,即 x4.(2)x(6) 36, x36.7集装箱在海上运输中被广泛使用,已知一个集装箱占空间(3 a)3,底面面积为(3 a)2,求该集装箱的高【解】 (3 a)3(3a)2(3 a)323 a.答:集装箱的高为 3a.2B组8若 5x

3、3 y20,则 105x103y_100_【解】 5 x3 y20,5 x3 y2,10 5x103y10 5x3 y10 2100.9若 10a20,10 b ,则 9a32b的值是_81_15【解】 10 a20,10 b ,1510 a10b20 100,1510 a b10 2, a b2.9 a32b(3 2)a32b3 2a32b3 2a2 b3 2(a b)3 2281.10若 xm4, xn8,则 x3m n_8_【解】 x3m n x3mxn( xm)3xn4 388.11计算:(1)(x3)2( x)5( x)10.【解】 原式 x6( x5)x10 x6x5x10 x65

4、10 x.(2)(9) 2n1 3 2(3) 3【解】 原式(3 2)2n1 (3233)3 4n2 353 4n3 .(3)(x3)2( x4)3( x6)3.【解】 原式 x6( x12)( x18) x6x12x181.(4) .2n 4 232n22n 1【解】 原式2n 4 2n 32n 22 n4 2n2 2 n3 2n22 222.12当细菌繁殖时,1 个细菌分裂成 2个,1 个细菌在分裂 n次后,数量变为 2n个有一种分裂速度很快的细菌,它每 12 min分裂一次如果现在盘子里有 1000个这样的细菌,那么 1 h后,盘子里有多少个细菌?2 h 后的数量是 1 h后的多少倍?【

5、解】 该种细菌每小时分裂 5次,1 h 后细菌的数量为 1000253.210 4(个),2 h后细菌的数量为 1000210个,(1000210)(100025)2 10252 532,即 2 h后的数量是 1 h后的 32倍3数学乐园13阅读下面的材料,并解答各题在形如 ab N的式子中,我们已经研究过两种情况:已知 a和 b,求 N,这是乘方运算已知 b和 N,求 a,这是开方运算现在我们研究第三种情况:已知 a和 N,求 b,我们把这种运算叫做对数运算定义:若 ab N(a0, a1, N0),则 b叫做以 a为底 N的对数,记做 blog aN.例如:因为 238,所以 log283.(1)根据定义计算:log 3814;log 331;log 310;如果 logx164,那么 x2(2)设 ax M, ay N,则 logaM x,log aN y(a0, a1, M, N均为正数),因为axay ax y,所以 ax y MN,从而 loga(MN) x y.即 loga(MN)log aMlog aN.这是对数运算的重要性质之一,我们还可以得出:loga(M1M2M3Mn)log aM1log aM2log aM3log aMn(a0, a1, M1, M2, M3, Mn均为正数),loga log aMlog aN(a0, a1, M, N均为正数)MN

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