(福建专版)2019高考数学一轮复习课时规范练20两角和与差的正弦、余弦与正切公式文.docx

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1、1课时规范练 20 两角和与差的正弦、余弦与正切公式基础巩固组1.(2017 山东,文 4)已知 cos x= ,则 cos 2x=( )34A.- B.14 14C.- D.18 182.cos 70sin 50-cos 200sin 40的值为( )A.- B.-32 12C. D.12 323.已知 ,且 cos =- ,则 tan 等于 ( )( ,32) 45 ( 4- )A.7 B.17C.- D.-7174.设 sin ,则 sin 2= ( )( 4+ )=13A.- B.-79 19C. D.19 795.若 tan = 2tan ,则 =( ) 5 cos( -310)si

2、n( - 5)A.1 B.2C.3 D.46.已知 cos +sin = ,则 sin 的值为 ( )( - 6) 435 ( +76)A. B. C.- D.-12 32 45 127.若 0bc B.bacC.cab D.acb 导学号 2419090017.(2017 江西重点中学盟校二模,文 14)已知 sin , ,则 cos( + 4)=14 (-32,- )的值为 . ( +712)答案:1.D cos 2x=2cos2x-1=2 -1= .(34)2 182.D cos 70sin 50-cos 200sin 40=cos 70sin 50+cos 20sin 40=cos 7

3、0sin 50+sin 70cos 50=sin(50+70)=sin 120= .323.B 因为 ,且 cos =- ,( ,32) 45所以 sin =- ,所以 tan = .35 34所以 tan .( 4- )=1-tan1+tan =1-341+34=174.A sin 2=- cos( 2+2 )=2sin2 -1( 4+ )=2 -1=- .(13)2 795.C 因为 tan = 2tan , 5所以cos( -310)sin( - 5)=sin( -310+ 2)sin( - 5)=sin( + 5)sin( - 5)4=sin cos 5+cos sin 5sin co

4、s5-cos sin 5= =3.tan +tan 5tan -tan5=3tan 5tan56.C cos +sin = cos + sin = ,( - 6) 32 32 435 cos + sin = .12 32 45 sin =-sin( +76) ( + 6)=- =- .(32sin +12cos ) 457.B 0 0,cos sin 12sin 11,acb. 故选 D.17.- 由 得 + ,15+ 38 (-32,- ) 4 (-54,-34)又 sin ,( + 4)=14所以 cos =- .( + 4) 154cos =cos( +712) ( + 4+ 3)7=cos cos -sin sin( + 4) 3 ( + 4) 3=-154 12-1432=- .15+ 38

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