2019春八年级数学下册20数据的分析20.2数据的波动程度(第2课时)学案(新版)新人教版.docx

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1、120.2 数据的波动程度(第 2 课时)学习目标1.会用样本方差去 估计总体方差;2.提高分析问题、解决问题的能力 .合作探究独立阅读 127128 页的内容完成:1.方差的公式 . 2.一组数据: -2,-1,0,x,1 的平均数是 0,则 x= ,方差 s2= . 3.已知 x1,x2,x3的平均数 =10,方差 s2=3,则 2x1,2x2,2x3的平均数为 ,方差为 x. 4.样本方差的作用是( )A.估计总体的平均水平B.表示样本的平均水平C.表示总体的波动大小D.表示样本的波动大小,从而估计总体的波动大小5.为了考察甲、乙两种农作物的长势,分别从中抽取了 10 株苗,测得苗高如下

2、单位:mm)甲:9,10,11,12,7,13,10,8,12,8 .乙:8,13,12,11,10,12,7,7,9,11 .请你经过计算后 回答如下问题:(1)哪种农作物的 10 株苗长得比较高?(2)哪种农作物的 10 株苗长得比较整齐?【参考答案】1.略; 2.2 2;3.20 12;4.D5.解:(1) (9+10+11+12+7+13+10+8+12+8)=10,x甲 =110(8+13+12+11+10+12+7+7+9+11)=10,x乙 =110从平均数看一样高 .(2) (9-10)2+(10-10)2+(11-10)2+(12-10)2+(7-10)2+(13-10)2+(10-10)2+(8-10)2+(12-10)2+(8-s2甲 =11010)2=3.6,(8-10)2+(13-10)2+(12-10)2+(11-10)2+(10-10)2+(12-10)2+(7-10)2+(7-10)2+(9-10)2+(11-s2乙 =11010)2=4.2.因为 ,所以甲种麦苗长势整齐 .s2甲 ”“、乙;5 .变大;6.(1)9.5 10(2)解: =9(分) .x乙 =10+8+7+9+8+10+10+9+10+910(10-9)2+(8-9)2+(10-9)2+(9-9)2=1.s2乙 =110(2)乙5

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