【公务员类职业资格】国家公务员行测(数字推理)-试卷7及答案解析.doc

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1、国家公务员行测(数字推理)-试卷 7及答案解析(总分:54.00,做题时间:90 分钟)一、数量关系(总题数:27,分数:54.00)1.数字推理给你一个数列,但其中缺少一项,要求你仔细观察数列的排列规律,然后从四个供选择的选项中选择你认为最合理的一项,来填补空缺项,使之符合原数列的排列规律。(分数:2.00)_2.2,6,28,174,( )(分数:2.00)A.1400B.1268C.800D.7983.12,13,28,87,352,( )(分数:2.00)A.715B.1756C.1765D.7854.172,84,40,18,( )(分数:2.00)A.22B.16C.7D.55.0

2、,1,3,8,22,63,( )(分数:2.00)A.122B.174C.185D.1966.2,5,13,35,97,( )(分数:2.00)A.214B.275C.312D.3367.14,2,2,10,160,4320, ( )(分数:2.00)A.4120B.42100C.69120D.694408.122,41,14,5,( )(分数:2.00)A.7B.4C.2D.一 19.,1,4,32,( ) (分数:2.00)A.512B.480C.320D.9610.5,5,15,75,( )(分数:2.00)A.425B.350C.455D.52511.18,36,72,144,( ),

3、576(分数:2.00)A.184B.226C.288D.34412.120,60,40,30,24,( )(分数:2.00)A.22B.20C.18D.1013.5,10,20,( ),80(分数:2.00)A.30B.40C.50D.6014.4,8,24,96,480,( )(分数:2.00)A.960B.3028C.1680D.288015.4,4,6,12,30,( )(分数:2.00)A.48B.64C.80D.9016.8,4,4,6,15,( )(分数:2.00)A.24B.30C.48D.6017.1,2,4,4,1,( ) (分数:2.00)A.B.C.D.18.3,5,1

4、3,43,( )(分数:2.00)A.86B.103C.144D.17719.6, 11, 17, ( ),45(分数:2.00)A.30B.28C.25D.2220.4,9,8, 11,1 2, ( )(分数:2.00)A.13B.14C.19D.1721.2, 4, 6, ( ), 16, 26(分数:2.00)A.8B.10C.12D.1422.101,102,203,305,508,( )(分数:2.00)A.813B.8013C.712D.70123.0,4,5,11,14,( )(分数:2.00)A.20B.21C.22D.2324.1,3,4,8,15,27,( )(分数:2.0

5、0)A.53B.38C.50D.4225.1,3,5,9,17,31,57,( )(分数:2.00)A.105B.89C.95D.13526.119,83,36,47,( )(分数:2.00)A.-37B.-1lC.11D.3727.6,7,8,13,15,21,( ),36(分数:2.00)A.27B.28C.31D.35国家公务员行测(数字推理)-试卷 7答案解析(总分:54.00,做题时间:90 分钟)一、数量关系(总题数:27,分数:54.00)1.数字推理给你一个数列,但其中缺少一项,要求你仔细观察数列的排列规律,然后从四个供选择的选项中选择你认为最合理的一项,来填补空缺项,使之符合

6、原数列的排列规律。(分数:2.00)_解析:2.2,6,28,174,( )(分数:2.00)A.1400 B.1268C.800D.798解析:解析:(2+1)2=6,(6+1)4=28,(28+1)6=174,(174+1)8=(1400)。3.12,13,28,87,352,( )(分数:2.00)A.715B.1756C.1765 D.785解析:解析:13=121+1,28=132+2,87=283+3,352=874+4,则下一项是 3525+5=(1765)。4.172,84,40,18,( )(分数:2.00)A.22B.16C.7 D.5解析:解析:每一项除以 2再减去 2得

7、到下一项。5.0,1,3,8,22,63,( )(分数:2.00)A.122B.174C.185 D.196解析:解析:每一项乘以 3再加上公差为一 1的等差数列。6.2,5,13,35,97,( )(分数:2.00)A.214B.275 C.312D.336解析:解析:每一项乘以 3再减去公比为 2的等比数列得到下一项。23-l=5、53-2=13、133-4=35、353-8=97、973-16=(275)。7.14,2,2,10,160,4320, ( )(分数:2.00)A.4120B.42100C.69120 D.69440解析:解析:等比数列变式。8.122,41,14,5,( )

8、(分数:2.00)A.7B.4C.2 D.一 1解析:解析:从第二项开始,每一项等于前一项加上 1的和除以 3,因此下一项为(5+1)3=(2)。9.,1,4,32,( ) (分数:2.00)A.512 B.480C.320D.96解析:解析:等比数列变式。10.5,5,15,75,( )(分数:2.00)A.425B.350C.455D.525 解析:解析:等比数列变式。11.18,36,72,144,( ),576(分数:2.00)A.184B.226C.288 D.344解析:解析:公比为 2的等比数列。1442=(288),(288)2=576。12.120,60,40,30,24,(

9、 )(分数:2.00)A.22B.20 C.18D.10解析:解析:等比数列变式。13.5,10,20,( ),80(分数:2.00)A.30B.40 C.50D.60解析:解析:公比为 2的等比数列,202=(40)。14.4,8,24,96,480,( )(分数:2.00)A.960B.3028C.1680D.2880 解析:解析:二级等比数列变式。15.4,4,6,12,30,( )(分数:2.00)A.48B.64C.80D.90 解析:解析:二级等比数列变式。16.8,4,4,6,15,( )(分数:2.00)A.24B.30C.48D.60 解析:解析:二级等比数列变式。17.1,

10、2,4,4,1,( ) (分数:2.00)A.B.C. D.解析:解析:数列先增后减,说明该数列不是作差得到规律。先增后减说明有一个因子在减少数列数值,可以考虑作商寻求这个比例因子,发现是一个三级等比数列。18.3,5,13,43,( )(分数:2.00)A.86B.103C.144D.177 解析:解析:每一项与自然数列的乘积加公差为 1的等差数列等于下一项。19.6, 11, 17, ( ),45(分数:2.00)A.30B.28 C.25D.22解析:解析:前两项相加,得到第三项,应填 11+17=(28)。20.4,9,8, 11,1 2, ( )(分数:2.00)A.13B.14C.

11、19D.17 解析:解析:和数列变式。21.2, 4, 6, ( ), 16, 26(分数:2.00)A.8B.10 C.12D.14解析:解析:典型和数列。前两项之和等于第三项,故 4+6=(10),6+(10)=16。22.101,102,203,305,508,( )(分数:2.00)A.813 B.8013C.712D.701解析:解析:题干较为迷惑之处在于数项均为小数,但仔细观察会发现该数列为典型和数列。305+508=(813),故选 A。23.0,4,5,11,14,( )(分数:2.00)A.20B.21C.22 D.23解析:解析:数列首项为 0,首先排除作商。尝试作差没有合

12、适的规律,转而考虑数列相邻项之和,得到和数列变式。24.1,3,4,8,15,27,( )(分数:2.00)A.53B.38C.50 D.42解析:解析:典型和数列。前三项之和等于第四项,依此类推,8+15+27=(50)。25.1,3,5,9,17,31,57,( )(分数:2.00)A.105 B.89C.95D.135解析:解析:典型和数列。前三项的和等于第四项,依此类推,17+31+57=(105)。26.119,83,36,47,( )(分数:2.00)A.-37B.-1l C.11D.37解析:解析:和数列变式。第二、三项之和为第一项,依此类推,36-47=(一 11)。27.6,7,8,13,15,21,( ),36(分数:2.00)A.27B.28 C.31D.35解析:解析:和数列变式。第一项+第二项=第四项,依此类推,故 13+15=(28)。

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