广东省2019年中考数学总复习第一部分知识梳理第二章方程与不等式第7讲分式方程及其应用课件.ppt

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1、第7讲 分式方程及其应用,1.(10分)(2017襄阳)分式方程 的解是_2.(10分)(2017永州)某水果店搞促销活动,对某种水果打八折出售,若用60元钱买这种水果,可以比打折前多买3斤设该种水果打折前的单价为x元,根据题意可列方程为_,x=9,3. (10分) (2017六盘水) 方程 =1的解为x=_. 4. (10分) (2017温州) 甲、乙工程队分别承接了160 m、200 m的管道铺设任务,已知乙比甲每天多铺设5 m,甲、乙完成铺设任务的时间相同,求甲每天铺设多少米. 设甲每天铺设x m,根据题意可列方程为_.,-2,5.(15分)(2018南通)解方程: ,解:去分母,得1=

2、x-1-3x+6. 解得x=2. 经检验,x=2是增根,分式方程无解,6.(15分)(2017朝阳)解分式方程:,解:去分母,得6x-3-4x-2=x+1.解得x=6. 经检验,x=6是分式方程的解,7. (30分) 从广州到某地可乘坐普通列车或高铁,已知高铁的行驶路程是400 km,普通列车的行驶路程是高铁的行驶路程的1.3倍.(1)求普通列车的行驶路程;(2)若高铁的平均速度(km/h)是普通列车平均速度(km/h)的2.5倍,且乘坐高铁所需时间比乘坐普通列车所需时间要少3 h,求高铁的平均速度.,解:(1)根据题意,得 4001.3=520(km). 答:普通列车的行驶路程是520 km. (2)设普通列车的平均速度是x km/h,则高铁的平均速度是2.5x km/h.根据题意,得 =3. 解得x=120. 经检验,x=120是原方程的解, 则高铁的平均速度是 1202.5=300(km/h). 答:高铁的平均速度是300 km/h.,

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