2019年高考数学二轮复习专题1高考22题各个击破3程序框图题专项练课件理.ppt

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1、1.3 程序框图题专项练,-2-,解答程序框图题的注意点 (1)要读懂程序框图,就要熟练掌握程序框图的三种基本结构,特别是循环结构. (2)准确把握控制循环的变量,变量的初值和循环条件,弄清在哪一步结束循环;弄清循环体和输入条件、输出结果. (3)对于循环次数比较少的可逐步写出,对于循环次数较多的,可先依次列出前几次循环结果,找出规律. (4)解答循环结构的程序框图(流程图)问题要注意输出循环次数的情况,防止多一次或少一次的错误.,-3-,一、选择题,二、填空题,答案,解析,-4-,一、选择题,二、填空题,2.(2018天津卷,理3)阅读下边的程序框图,运行相应的程序,若输入N的值为20,则输

2、出T的值为( ) A.1 B.2 C.3 D.4,答案,解析,-5-,一、选择题,二、填空题,3.某地区乘坐出租车收费办法如下:不超过2千米收7元,超过2千米时,每车收燃油附加费1元,并且超过的里程每千米收2.6元(其他因素不考虑),计算收费标准的框图如图所示,则处应填( ) A.y=2.0x+2.2 B.y=0.6x+2.8 C.y=2.6x+2.0 D.y=2.6x+2.8,答案,解析,-6-,一、选择题,二、填空题,4.(2018全国卷2,理7)为计算 设计了下面的程序框图,则在空白框中应填入 ( ) A.i=i+1 B.i=i+2 C.i=i+3 D.i=i+4,答案,解析,-7-,一

3、选择题,二、填空题,5.我国南宋时期的数学家秦九韶(约12021261)在他的著作数书九章中提出了多项式求值的秦九韶算法.如图所示的框图给出了利用秦九韶算法求多项式的一个实例.若输入的n=5,v=1,x=2,则程序框图计算的是( ) A.25+24+23+22+2+1 B.25+24+23+22+2+5 C.26+25+24+23+22+2+1 D.24+23+22+2+1,答案,解析,-8-,一、选择题,二、填空题,6.(2018福建厦门外国语学校一模,理7)如果执行如图的程序框图,那么输出的值是( ) A.2 010 B.-1 C. D.2,答案,解析,-9-,一、选择题,二、填空题,7

4、执行如图的程序框图,则输出K的值为( ) A.98 B.99 C.100 D.101,答案,解析,-10-,一、选择题,二、填空题,8.下面程序框图是为了求出满足3n-2n1 000的最小偶数n,那么在A.A1 000和n=n+1 B.A1 000和n=n+2 C.A1 000和n=n+1 D.A1 000和n=n+2,答案,解析,-11-,一、选择题,二、填空题,9.(2018宁夏银川一中一模,理5)阅读程序框图,如果输出的函数值在区间 内,则输入的实数x的取值范围是( ) A.(-,-2 B.-2,-1 C.-1,2 D.2,+),答案,解析,-12-,一、选择题,二、填空题,10.(2

5、018河南郑州三模,理6)执行如图所示的程序框图,若p=0.8,则输出的n=( ) A.3 B.4 C.5 D.6,答案,解析,-13-,一、选择题,二、填空题,11.(2018广东揭阳模拟,理7)如图所示的程序框图是为了求出12399100的常用对数值,那么在空白判断框中,应该填入 .,答案,解析,-14-,一、选择题,二、填空题,12.(2018北京朝阳期末,理9)执行如图所示的程序框图,输出S的值为 .,答案,解析,-15-,一、选择题,二、填空题,13.执行如图所示的程序框图,那么输出的值是 .,答案,解析,-16-,一、选择题,二、填空题,14.执行下图程序框图,若输入的x,t均为2,则输出的S= .,答案,解析,

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