GOST R 8 840-2013 State system for ensuring the uniformity of measurements State verification schedule for means measuring absolute pressure in the range 1 - 1·10 6 Pa《确保测量一致性的国家系统.pdf

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1、 8.840 2013 1 1106 8.8402013 II 1 - . . ( . . ) 2 , 206.4 3 17 2013 . 1165-. 4 1.02012 ( 8). ( 1 ) , . () . , (gost.ru) , 2014 , 8.8402013 1 1 1106 State system for ensuring the uniformity of measurements. State verification schedule for means measuring absolute pressure in the range 1 1106 Pa 2015

2、0101 1 1 1106 . . 2 2.1 2.1.1 . 2.1.2 : - ; - ; - . 2.1.3 , , .110-1 7105 2.1.4 110-1 1103 , S, 1,310-3, 10- . 3,210-3 + 7,0 10-5 , p , . .uc: 3,610-3 + 5,010-5, p , . 2.1.5 . 1102 1,3105 . S, 2,110-2, 10- . .4,310-2 + 7,010-6 , p , . uc: 5,210-2 +4,910-6 , p , . 2.1.6 . 7103 7105 , 8.8402013 2 S, 0

3、,2 1 , 10- . 0,3 7 . uc: 0,5 7,8 . 2.1.7 , . 2.1.8 . 2.1.9 . 2.2 2.2.1 - . 2.2.2 - : - 110-1 1103 ; - 1102 1,3105 . 2.2.2.1 () S - , 10- , : - 1,810-3 ; - 3,010-2 . - : - 3,210-3 + 7,010-5 , , , ; - 4,310-2 + 7,010-6 , , , . 2.2.2.2 - . 2.2.3 - 1 1,3105 , 7 1000 97 105 . 2.2.3.1 S - , 10- , : - 2,31

4、0-3 + 9,010-5 , 1 1103 ; - 3,510-2 + 9,0 10-6 , 1103 1,3105 . 2.2.3.2 S , 10- , : - 1,3 7 130 ; - 1,3 10 130 1000 . 2.2.3.3 S 1,3 . 2.2.3.4 () 1 . 3 () 3.1 1- 3.1.1 1- : - - 0,5 280 , 8.8402013 3 - 0,27 1000 , - , 0 1 . - . 0 1 . - 0 1 . 3.1.2 1 5 100 . 3.1.3 1 () 2- . 3.2 2- 3.2.1 2- : - 88 109 , -

5、 - 0,5 110 , - . 10 1000 , - . 0 1 , - . 0 1 . - 0 1 . 3.2.2 2- 10 250 . 3.2.3 1- 2- 1:2. 3.2.4 2- (, ) 3 - . 3.3 3 - 3.3.1 3- : - 57 107 , - 0,2 107 , - , 0 1 . - . 0 1 . - 0 1 . 3.3.2 3- 30 500 . 3.3.3 2- 3- 1:1,5 1:2 , . 3.3.4 3- (, ) . 4 4.1 : - 40 109 , - - 0,5 110 , - 0 1 , - . 40 106 , - 68 1

6、07 , - 0 1 . 8.8402013 4 4.2. 26 10000 . 4.3 1:1,5 , 1:4 1:3 - . 8.8402013 5 . 1 106 - 0 , 5 2 8 0 = 1 0 2 8 0 , 2 7 1 0 0 0 = 5 1 0 0 , 0 1 = 5 1 0 0 88 1 0 9 = 2 0 - 0 , 5 1 1 0 = 2 0 10 1 0 0 0 = 1 0 2 0 0 , 0 1 = 2 0 2 5 0 57 1 0 7 = 3 0 0 , 2 1 0 7 = 5 0 , 0 1 = 3 0 5 0 0 40 1 0 9 = 2 6 2 0 0 - 0 , 5 1 1 0 = 3 3 40 1 0 6 = 2 7 68 1 0 7 = 5 0 0 1 = 0 , 0 4 1 0 0 1 = 1 0 0 3 2 0 7 1 3 0 S= 1 ,3

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