【考研类试卷】考研数学二(一元函数积分学)-试卷7及答案解析.doc

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1、考研数学二(一元函数积分学)-试卷 7 及答案解析(总分:56.00,做题时间:90 分钟)一、选择题(总题数:2,分数:4.00)1.选择题下列每题给出的四个选项中,只有一个选项符合题目要求。(分数:2.00)_2.设f(x)dx=x 2 +C,则xf(1-x 2 )dx 等于( )(分数:2.00)A.B.C.2(1-x 2 ) 2 +CD.-2(1-x 2 ) 2 +C二、填空题(总题数:6,分数:12.00)3.= 1 (分数:2.00)填空项 1:_4.= 1 (分数:2.00)填空项 1:_5.= 1 (分数:2.00)填空项 1:_6.设 f(x)是以 T 为周期的连续函数,且

2、F(x)= (分数:2.00)填空项 1:_7.设 f(x)C1,+),广义积分 (分数:2.00)填空项 1:_8.= 1 (分数:2.00)填空项 1:_三、解答题(总题数:20,分数:40.00)9.解答题解答应写出文字说明、证明过程或演算步骤。(分数:2.00)_10. (分数:2.00)_11.求 (分数:2.00)_12.求 (分数:2.00)_13.求 (分数:2.00)_14.求 (分数:2.00)_15.求 (分数:2.00)_16.求 (分数:2.00)_17. (分数:2.00)_18. (分数:2.00)_19. (分数:2.00)_20. (分数:2.00)_21.

3、分数:2.00)_22. (分数:2.00)_23. (分数:2.00)_24.xtanxsec 4 dx(分数:2.00)_25. (分数:2.00)_26.arcsinxarccosxdx(分数:2.00)_27. (分数:2.00)_28. (分数:2.00)_考研数学二(一元函数积分学)-试卷 7 答案解析(总分:56.00,做题时间:90 分钟)一、选择题(总题数:2,分数:4.00)1.选择题下列每题给出的四个选项中,只有一个选项符合题目要求。(分数:2.00)_解析:2.设f(x)dx=x 2 +C,则xf(1-x 2 )dx 等于( )(分数:2.00)A.B. C.2(1-

4、x 2 ) 2 +CD.-2(1-x 2 ) 2 +C解析:解析:二、填空题(总题数:6,分数:12.00)3.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:4.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:因为5.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:6.设 f(x)是以 T 为周期的连续函数,且 F(x)= (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:7.设 f(x)C1,+),广义积分 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:

5、解析:令8.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:1)解析:解析:三、解答题(总题数:20,分数:40.00)9.解答题解答应写出文字说明、证明过程或演算步骤。(分数:2.00)_解析:10. (分数:2.00)_正确答案:(正确答案: )解析:11.求 (分数:2.00)_正确答案:(正确答案:因为(3+sinxcosx)“=cos2x,所以 )解析:12.求 (分数:2.00)_正确答案:(正确答案:由 )解析:13.求 (分数:2.00)_正确答案:(正确答案: )解析:14.求 (分数:2.00)_正确答案:(正确答案: )解析:15.求 (分数:2.00)_

6、正确答案:(正确答案: )解析:16.求 (分数:2.00)_正确答案:(正确答案: )解析:17. (分数:2.00)_正确答案:(正确答案:令 sinx-cosx=a(sinx+2cosx)+b(sinx+2cosx)“,则 )解析:18. (分数:2.00)_正确答案:(正确答案: )解析:19. (分数:2.00)_正确答案:(正确答案: )解析:20. (分数:2.00)_正确答案:(正确答案: )解析:21. (分数:2.00)_正确答案:(正确答案: )解析:22. (分数:2.00)_正确答案:(正确答案: )解析:23. (分数:2.00)_正确答案:(正确答案: )解析:24.xtanxsec 4 dx(分数:2.00)_正确答案:(正确答案: )解析:25. (分数:2.00)_正确答案:(正确答案: )解析:26.arcsinxarccosxdx(分数:2.00)_正确答案:(正确答案: )解析:27. (分数:2.00)_正确答案:(正确答案:令 e x =t,dx= )解析:28. (分数:2.00)_正确答案:(正确答案: )解析:

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