【考研类试卷】考研数学二(一元函数积分学)-试卷9及答案解析.doc

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1、考研数学二(一元函数积分学)-试卷 9 及答案解析(总分:56.00,做题时间:90 分钟)一、选择题(总题数:2,分数:4.00)1.选择题下列每题给出的四个选项中,只有一个选项符合题目要求。(分数:2.00)_2.设 M= (分数:2.00)A.NPMB.MPNC.NMPD.PMN二、填空题(总题数:6,分数:12.00)3.= 1 (分数:2.00)填空项 1:_4.= 1 (分数:2.00)填空项 1:_5.= 1 (分数:2.00)填空项 1:_6.= 1 (分数:2.00)填空项 1:_7.设 f(x)= (分数:2.00)填空项 1:_8.= 1 (分数:2.00)填空项 1:_

2、三、解答题(总题数:20,分数:40.00)9.解答题解答应写出文字说明、证明过程或演算步骤。(分数:2.00)_10. (分数:2.00)_11. (分数:2.00)_12. (分数:2.00)_13. (分数:2.00)_14. (分数:2.00)_15. (分数:2.00)_16. (分数:2.00)_17. (分数:2.00)_18. (分数:2.00)_19. (分数:2.00)_20.设 f(x 2 -1)= (分数:2.00)_21.设 f(lnx)= (分数:2.00)_22. (分数:2.00)_23. (分数:2.00)_24. (分数:2.00)_25.x 2 arcta

3、nxdx(分数:2.00)_26.f(arccosx) 2 dx(分数:2.00)_27.设 x-1,求 (分数:2.00)_28.当 x0 时,f(x)=x,设 g(x)= (分数:2.00)_考研数学二(一元函数积分学)-试卷 9 答案解析(总分:56.00,做题时间:90 分钟)一、选择题(总题数:2,分数:4.00)1.选择题下列每题给出的四个选项中,只有一个选项符合题目要求。(分数:2.00)_解析:2.设 M= (分数:2.00)A.NPMB.MPNC.NMPD.PMN 解析:解析:二、填空题(总题数:6,分数:12.00)3.= 1 (分数:2.00)填空项 1:_ (正确答案:

4、正确答案:*)解析:解析:4.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:5.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:6.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:7.设 f(x)= (分数:2.00)填空项 1:_ (正确答案:正确答案:e -1 -1)解析:解析:8.= 1 (分数:2.00)填空项 1:_ (正确答案:正确答案:*)解析:解析:三、解答题(总题数:20,分数:40.00)9.解答题解答应写出文字说明、证明过程或演算步骤。(分数:2.00)_解析:10. (分数

5、2.00)_正确答案:(正确答案:令 )解析:11. (分数:2.00)_正确答案:(正确答案: )解析:12. (分数:2.00)_正确答案:(正确答案: )解析:13. (分数:2.00)_正确答案:(正确答案: )解析:14. (分数:2.00)_正确答案:(正确答案: )解析:15. (分数:2.00)_正确答案:(正确答案:令 )解析:16. (分数:2.00)_正确答案:(正确答案: )解析:17. (分数:2.00)_正确答案:(正确答案: )解析:18. (分数:2.00)_正确答案:(正确答案: )解析:19. (分数:2.00)_正确答案:(正确答案:令 =t,dx=6t

6、 5 dt,则 )解析:20.设 f(x 2 -1)= (分数:2.00)_正确答案:(正确答案:由 )解析:21.设 f(lnx)= (分数:2.00)_正确答案:(正确答案:由 f(lnx)= 由 C 1 =1+C 2 ,取 C 2 =C 得f(x)dx= )解析:22. (分数:2.00)_正确答案:(正确答案: )解析:23. (分数:2.00)_正确答案:(正确答案: )解析:24. (分数:2.00)_正确答案:(正确答案: )解析:25.x 2 arctanxdx(分数:2.00)_正确答案:(正确答案: )解析:26.f(arccosx) 2 dx(分数:2.00)_正确答案:(正确答案: )解析:27.设 x-1,求 (分数:2.00)_正确答案:(正确答案:当-1x0 时, 当 x0 时, )解析:28.当 x0 时,f(x)=x,设 g(x)= (分数:2.00)_正确答案:(正确答案: )解析:

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