2019年高考数学大二轮复习第三篇考前回扣查缺补漏回扣落实(五)立体几何课件理.ppt

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回扣落实(五) 立体几何,答案 A,3注意图形的翻折与展开前后变与不变的量以及位置关系对照前后图形,弄清楚变与不变的元素后,再立足于不变的元素的位置关系与数量变化去探求变化后的元素在空间中的位置与数量关系,回扣问题2 如图是正方体的平面展开图,在这个正方体中,AN与BG平行;AN与EF是异面直线;AN与DM成60角;DM与EF平行以上四个命题中正确的命题是 A B C D 答案 D,4不清楚空间线面平行与垂直关系中的判定定理和性质定理,忽视判定定理和性质定理中的条件,导致判断出错如由,l,ml,易误得出m的结论,就是因为忽视面面垂直的性质定理中m的限制条件,回扣问题3 设a,b为两条直线,为两个平面,且a,a,则下列结论中不成立的是 A若b,ab,则a B若a,则a C若ab,b,则a D若,a,ba,则b 答案 D,5(1)求线面角时,得到的是直线方向向量和平面法向量的夹角的余弦,容易误以为是线面角的余弦 (2)求二面角时,两法向量的夹角有可能是二面角的补角,要注意从图中分析,

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