八年级数学上册第十四章整式的乘法与因式分解14.2乘法公式14.2.2第2课时乘法公式的综合运用同步训练(新版)新人教版.doc

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1、1第 2课时 乘法公式的综合运用学生用书 P851( x y z)2( ) 22 y( ) y2,两个括号内应填( )A x y B y zC x z D x y z2为了应用平方差公式计算(2 x y z)(y2 x z),下列变形正确的是( )A2 x( y z)2B2 x( y z)2x( y z) C y(2 x z)y(2 x z)D z(2 x y)z(2 x y)3整式 A与 m22 mn n2的和 是( m n)2,则 A_ _42016荆州将二次三项式 x24 x5 化成( x p)2 q的形式应为_ _5利用乘法公式计算:(1)(2x3 y)2( y3 x)(3x y);(

2、2)(x y)(x2 y2)(x y)(x4 y4);(3)(a2 b3)( a2 b3);(4)(x y)2( x y)2(x2 y2);(5)(m n3) 2.262016衡阳先化简,再求值:( a b)(a b)( a b)2,其中 a1, b .127先化简(2 x1) 2(3 x1)(3 x1)5 x(x1),再任选一个你喜欢的数代替 x,求原代数式的值82015滨海一模已知 x24 x10,求代数式(2 x1) 2( x2)( x2) x(x4)的值92016广安我国南宋数学家杨辉用三角形解释二 项和的乘方规律,称之为“杨辉三角” 如图 14-2-3,杨辉三角给出了( a b)n(

3、n1,2,3,4,)的展开式的系数规律(按展开式中 a的次数由大到小的顺序)3图 14-2-3请依据上述规律,写出 的展开式中 含 x2 014项的系数是_ _(x2x)2 016 参考答案【知识管理】不变符号 改变符号 bc bc【归类探究】例 1 (1)(5 a3b2 ab)(3 ab32 b2) (2)5 a3b(2 ab3 ab32 b2) (3)(5 a3b3 ab3)(2 ab2 b2)例 2 (1) a22 ab b2c 2 (2) x22 x19 y2(3)9x212 xy4 y2 x y32 116例 3 ( x2 y2)2 25【当堂测评】1A 2.B 3.B4(1)3 y4 z (2)3 y4 z (3)3 y4 z (4)3 y4 z【分层作业】1C 2.C 3.4 mn 4.( x2) 215(1) 5x212 xy10 y2 (2) x8 y8 (3) a24 b212 b9 (4)2 x42 y4 (5)m2 n292 mn6 m6 n62 a22 ab 1479 x2 2(答案不唯一)8794 032

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